He also supposes that the total cost of keeping n Tvs in inventory is by c(n) = o,3n^2 + 5000.
how many TVs must retailer keep in inventory and sell to maximize his profit?
profit = (600-0.3n) *n - (0.3n^2+5000)
d(profit)/dn = -1.2n + 600 = 0
n = 500
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