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##### physics problem about linear momentum

label Physics
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particle 1 of mass M movies with speed v in the +x direction and has an elastic collision with particle 2 (mass=3M) that was orginally at rest. after the collision, particle 2 is moving in the +x direction. what is its speed?

Oct 23rd, 2017

Momentum is always conserved.
Total momentum before = total momentum after
mv = m(v1-v1 after collision) + (3m)(v2-v2 after collision)
Simplify:
v =( v1-v1 after collision)+ 3(v2-v2 after collision)

In elastic collisions, KE is conserved.
Total KE before = total KE after collision
½mv² = ½m(v1-v1 after collision)² + ½(3m)(v2-v2 after collison)²
Simplify:
v² = (v1-v1 after collision)² + 3(v2- v2 after collision)²

therefore:
v =( v1-v1 after collision) + 3(v2_v2 after collision)
v² = (v1-v1 after collision)² + 3(v2_v2after collision)²

Apr 13th, 2015

Momentum is always conserved.
Total momentum before = total momentum after
mv = m(v1-v1 after collision) + (3m)(v2-v2 after collision)
Simplify:
v =( v1-v1 after collision)+ 3(v2-v2 after collision)

In elastic collisions, KE is conserved.
Total KE before = total KE after collision
½mv² = ½m(v1-v1 after collision)² + ½(3m)(v2-v2 after collison)²
Simplify:
v² = (v1-v1 after collision)² + 3(v2- v2 after collision)²

therefore:
v =( v1-v1 after collision) + 3(v2_v2 after collision)

v1=v- 3(v2-v2 after collision) +v1 after collision

v2=v/3-( v1-v1 after collision)/3+v2 after collision

v² = (v1-v1 after collision)² + 3(v2-v2after collision)²

Apr 13th, 2015

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Oct 23rd, 2017
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Oct 23rd, 2017
Oct 24th, 2017
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