S1=7KW+3KVAR =7000+3000j VA = 7+3j (KVA)
S2=4KW at 0.85 power factor =4000[cos(theta)+jsin(theta)]
=3400 + j2107 VA =3.4+2.107j (KVA)
Since loads are in parallel, so total complex power would be:
=(7+3j) +( 3.4 + 2.107 j) (KVA)
=10.4 + 5.107 j (KVA)
=10400+5107 j (VA)
=11586 (with angle of /_ 26.15 degree ) (VA) Ans
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