m(t) = 15e^{ā0.087t},

where

m(t)

is measured in grams. After how many days is there only 3 g remaining? (Round your answer to the nearest whole number.) days

m(t) = 15e^{ā}^{0.087}^{t} =3

e^{-0.087t = 3/15 =0.2}

^{t = ln(0.2)/(-0.087) = -1.60944/ (-0.087) =18.499=18.5 days=18 days or 19 days}

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