The problem I'm having is, I have 6 fair coins. I need to know the total amount of possible outcomes, where order and repetition do not matter... I have been stuck for the past 2 hours and I would love some help.
2^6 = 64.....
First coin can be arranged iin 2 ways, second in two ways.....similarly all other coins be arranged in 2,2 ways....all in all 2x 2 x 2 x2x2x2 = 64
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