Having problems trying to solve this problem : y varies directly as x^2. When x =6, y=108. Determine teh value of y when x= 4

the law governing is: y=kx^2

x=6, y=108

k= y/x^2= 108/36=3

k=3

y=3x^2= 3(4^2)= 48...........................................

so y=48

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