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how do you solve this equation?

Algebra
Tutor: None Selected Time limit: 0 Hours

log4(x+6)+log4x=2

4 being the base 

Apr 14th, 2015

log4(x+6)+log4x=2

Now by logarithmic property.

log4(x+6)x=2

Taking exponential on bothsides, we get

 (x+6)x = 4^2

x^2+6x=16

x^2+6x-16=0

x^2-2x+8x-16=0

x(x-2)+8(x-2)=0

(x-2)(x+8)=0

x=2

&

x=-8

Apr 14th, 2015

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