a 1.05 m solution of HNO3 in 2.13 kg H2O

label Chemistry
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i have to determine the number of grams needed for this problem

Apr 14th, 2015

mass=moles*MM

=1.05*63.01= 66.17g.....................................................................................................................................

Apr 14th, 2015
Determine the number of grams of solute needed to make each of the following molal solutions.. for that solution the answer isnt correct for the equation
Apr 14th, 2015

density of water= 1000kg/1000ltrs

volume=2130 cm^3

1000=1.05

2130=?

moles= 2130*1.05/1000= 2.24moles

mass= moles*RMM= 2.24*63.01=140.9 g

Apr 14th, 2015

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Apr 14th, 2015
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Apr 14th, 2015
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