Water at a pressure of 3.8 atm at street level flows into an office building at

Physics
Tutor: None Selected Time limit: 1 Day

Apr 14th, 2015

By continuity equation:
v2 = (A1v1) / A2 = (d1/d2)²v1 = (5.6/2.6)²* 0.45 = 2.1 m/s
flow velocity=2.1 m/s
By Bernoulli’s Equation:
P1 + ρgh1 + ½ρ (v1)²= P2 + ρgh2 + ½ρ(v2)²
[v1² -v2²] /2 = (P2-P1)/ ρ + g(h2 -h1)
(0.45²- 2.1²)/2 = (P2-P1)/ 1000 + 9.8*20
-2.10375= (P2-P1)/ 1000 + 196
(P2-P1) = - 198103.75 Pa
P2 = P1-198103.75

P1 = 3.8atm = 385035 Pa
P2 = 385035-198103.75

pressure= 186931.25 Pa ( gauge pressure)
  flow velocity=2.1 m/s

Apr 14th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Apr 14th, 2015
...
Apr 14th, 2015
Dec 5th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer