Water at a pressure of 3.8 atm at street level flows into an office building at

Physics
Tutor: None Selected Time limit: 1 Day

Apr 14th, 2015

By continuity equation:
v2 = (A1v1) / A2 = (d1/d2)²v1 = (5.6/2.6)²* 0.45 = 2.1 m/s
flow velocity=2.1 m/s
By Bernoulli’s Equation:
P1 + ρgh1 + ½ρ (v1)²= P2 + ρgh2 + ½ρ(v2)²
[v1² -v2²] /2 = (P2-P1)/ ρ + g(h2 -h1)
(0.45²- 2.1²)/2 = (P2-P1)/ 1000 + 9.8*20
-2.10375= (P2-P1)/ 1000 + 196
(P2-P1) = - 198103.75 Pa
P2 = P1-198103.75

P1 = 3.8atm = 385035 Pa
P2 = 385035-198103.75

pressure= 186931.25 Pa ( gauge pressure)
  flow velocity=2.1 m/s

Apr 14th, 2015

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