a) If M = 20, then the cost of seizing x% of illegal software is C(x) = 20x/(50 - 0.5x) in millions of dollars.

b) If x = 50, then C(50) = 20*50/(50 - 50*0.5) = $40 mln

C(60) = 20*60/(50 - 0.5*60) = $60 mln

C(70) = 20*70 /(50 - 0.5*70) = $93.33 mln

C(80) = 20*80/(50 - 0.5*80) = $160 mln

C(90) = 20*90/(50 - 0.5 * 90) = $360 mln

c) lim_{x to 100-} C(x) = +infty because the numerator tends to 2000 while the denominator tends to zero.

In practice it means that attempts to seize 100% of illegal software become prohibitively expensive.

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