A small lake is stocked with a certain species of fish. The fish population is m

label Algebra
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schedule 1 Day
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P = 

18
1 + 4e−0.8t

(a) Find the fish population after 2 years. (Round your answer to the nearest whole fish.)

 fish

(b) After how many years will the fish population reach 9000 fish? (Round your answer to two decimal places.)
 yr
Apr 14th, 2015

a) P(2) = 18000/(1+ 4*e^{-0.8*2}) = 9958

b) From the equation 18000/(1+ 4*e^{-0.8*2}) = 9000 we get 1+ 4*e^{-0.8t} = 18000*9000= 2;

4*e^{-0.8t} = 1; e^{-0.8t} = 1/4 = 0.25; -0.8t = ln0.25; and

t = ln0.25/(-0.8) = 1.73 years.

Apr 14th, 2015

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