P =

(a) Find the fish population after 2 years. (Round your answer to the nearest whole fish.)

a) P(2) = 18000/(1+ 4*e^{-0.8*2}) = 9958

b) From the equation 18000/(1+ 4*e^{-0.8*2}) = 9000 we get 1+ 4*e^{-0.8t} = 18000*9000= 2;

4*e^{-0.8t} = 1; e^{-0.8t} = 1/4 = 0.25; -0.8t = ln0.25; and

t = ln0.25/(-0.8) = 1.73 years.

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