a. f'(x) = 3x^2 -1
f'(0) = -1
therefore, slope = -1 at point (0, -1)
use point/slope formula to find equation of line
y+1 = -1(x - 0)
y+1 = -x
y = -x - 1
b. since the derivative is negative, the slope is negative at the function is decreasing.
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