# find derivative of function in calculus

label Calculus
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Apr 15th, 2015

a. (2x2 – 5x + 3x–2 + 4x–3)' = 4x – 5 – 6x–3 – 12x–4

b. (5t3 + t2)(2t – 4) = (5t3 + t2)' (2t – 4) + (5t3 + t2) (2t – 4)' = (15t2 + 2t)(2t – 4) + 2(5t3 + t2)

c. (x2 – 2x + 5)/x = [(x2 – 2x + 5)' x – (x2 – 2x + 5) x' ]/x2 = [(2x – 2) x – (x2 – 2x + 5) ]/x2

d. da/db = [(7 – 2b)3]' = 3(7 – 2b)2( – 2)

Apr 15th, 2015

hello,

For #d:

a=(7-2b)^3

why do you use da/db and the [ ] ' symbols? When I type this in to try and solve this way I get error messages.

Apr 17th, 2015

I was not sure what was the independent variable in d). If it were x as in the previous items, then the function a = (7 - 22)^3 is a constant and its derivative = 0. So, da/db means that the derivative is taken by the variable b. The symbol [..] ' also means a derivative but does not specify by what variable.

Apr 17th, 2015

I was not sure what was the independent variable in d). If it were x as in the previous items, then the function a = (7 - 22)^3 is a constant and its derivative = 0. So, da/db means that the derivative is taken by the variable b. The symbol [..] ' also means a derivative but does not specify by what variable.

Apr 17th, 2015

thanks so much, you make it so easy to understand

Apr 17th, 2015

thanks so much, you make it so easy to understand

Apr 17th, 2015

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Apr 15th, 2015
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Apr 15th, 2015
Nov 20th, 2017
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