find velocity of function in calculus

Calculus
Tutor: None Selected Time limit: 1 Day

Apr 15th, 2015

a.  Let v0 = 200 ft/sec

b.  v(t) = -32t + 200

v(5) = -32(5) + 200 = 40 ft/sec

c.  max height when v(t) = 0

0 = -32t + 200

32t = 200

t = 6.25 sec

d.  will hit ground in 2(6.25) = 12.5 sec

e.  v(12.5) = -32(12.5) + 200 = -200 ft/sec


Apr 15th, 2015

In the equation solution where does v(t) come from? For a the equation being used:


Not understanding how b - e were arrived at when looking at function to use.

vO=200ft/sec

h(t) = -16t^2 + 200(t)

Apr 16th, 2015

Hi Denise. In calculus, v(t) is the derivative of the distance formula h(t).

Apr 16th, 2015

Sorry Denise. I'm constantly in and out of my house tutoring students at the library.  I forget to log off studypool so it seems I'm here when I'm not.  I'll try to answer your questions when I can. Sorry that I can't give a schedule since it's constantly changing.

Apr 16th, 2015

Ok thanks for all the help, you have no idea how much this is helping me understand calculus. It just seems so foriegn to me since it is the first time I have ever did it. Just want to make sure I understand it completely for future reference. 

So with the fucntion provided:

h(t) = -16t^2 + 200(t)

a. vO=200ft/sec

b. using the function provided how did it arrive at

v(t) = -32t + 200

v(5) = -32(5) + 200 = 40 ft/sec

c.  using the function provided how did it arrive at

max height when v(t) = 0

0 = -32t + 200

32t = 200

t = 6.25 sec

d.  using the function provided how did it arrive at

will hit ground in 2(6.25) = 12.5 sec

e.  using the function provided how did it arrive at

v(12.5) = -32(12.5) + 200 = -200 ft/sec



Apr 16th, 2015

Denise, what you really need is a calculus tutor. I would love to do it. But you would benefit the most from one on one help in person. If you lived near me I could tutor you at the local library. Calculus is just a little too difficult to do just over the internet.

Apr 16th, 2015

omg I was confused at how you arrived at -32t + 200 forgetting to apply 

d/dt ((-16)t^2)

= 2(-16)t^2-1

= -32t^1

= -32t


I learn best from the steps being shown, I guess I did not word it the right way.  So sorry but I do wish I could have one on one tutoring as a student, that would be great.

Apr 16th, 2015

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Apr 15th, 2015
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Apr 15th, 2015
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