Find the vertex of the following parabola, f(x)=-5(x+1)^2-5

f(x)=-5(x+1)^2-5

f(x)=-5(x^2+2x+1)-5= -5x^2-10x-10

x coordinate is

-b/2a= 10/-10= -1

substituting in original equation,

y= -5

so the vertex of the parabola is at (-1,-5)

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