Statistic assignments

Mathematics
Tutor: None Selected Time limit: 1 Day

Compute the mean and variance of the following probability distribution. (Round your answers to 2 decimal places.)


XP(X)
4      .1      
8      .30      
12      .25      
16      .35      

Mean=

Variance=

Apr 15th, 2015

Mean =11.4

Variance=16.44

mean_var_apr15.xlsx 

Apr 15th, 2015

Can I send some questions can you answer it within 15 mins and i will pay for that 


Apr 15th, 2015

A random sample of 23 items is selected from a population. To determine the appropriate critical t-value what number of degrees of freedom should be used?

24
22
31
26

which one 

Apr 15th, 2015

If it does not take much time, I will answer. Post in easy questions. I avoid bidding. 

Apr 15th, 2015

22

(23-1)

Apr 15th, 2015

An experiment involves selecting a random sample of 276 middle managers study. One item of interest is their mean annual income. The sample mean is computed to be $35,420 and the sample standard deviation is $2,228. What is the standard error of the mean?

$2,228
$16.613
$134.110
 $2,228 


Apr 15th, 2015

Standard error =2228/sqrt(276) = 134.1098 = 134.11

Third option

Apr 15th, 2015

According to the Census Bureau, 3.40 people reside in the typical American household. A sample of 21 households in Arizona retirement communities showed the mean number of residents per household was 2.70 residents. The standard deviation of this sample was 1.17 residents. At the .10 significance level, is it reasonable to conclude the mean number of residents in the retirement community household is less than 3.40 persons?


a.State the null hypothesis and the alternate hypothesis. (Round your answer to 2 decimal places.)
 H0: μ ≥
 H1: μ <

b.

State the decision rule for .10 significance level. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

 RejectH0 if t<

c.

Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

 Value of the test statistic

d.

Is it reasonable to conclude the mean number of residents in the retirement community household is less than 3.40 persons?

  H0. Mean number of residents  less than 3.40 persons.

Apr 15th, 2015

The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 20 chickens shows they laid an average of 22 eggs per month with a standard deviation of 2.7 eggs per month.


(a-1)What is the value of the population mean?
(a-2)What is the best estimate of this value?

(c)

For a 90 percent confidence interval, the value of t  is (Round your answer to 3 decimal places.)


(d)

The 90 percent confidence interval for the population mean is  to  (Round your answers to 3 decimal places.)


(e-1)Would it be reasonable to conclude that the population mean is 24 eggs?
(e-2)What about 27 eggs?

Apr 15th, 2015

A sample of 36 observations is selected from a normal population. The sample mean is 21, and the population standard deviation is 5. Conduct the following test of hypothesis using the 0.05 significance level.


H0 : μ ≤ 20
H1 : μ > 20

a.Is this a one- or two-tailed test?
"Two-tailed"-the alternate hypothesis is different from direction.
"One-tailed"-the alternate hypothesis is greater than direction.

b.What is the decision rule? (Round your answer to 2 decimal places.)

 H0,when z > 

c.What is the value of the test statistic? (Round your answer to 2 decimal places.)

 Value of the test statistic

d.What is your decision regarding H0?
Do not reject
Reject

There is  evidence to conclude that the population mean is greater than 20.

e.What is the p-value? (Round your answer to 4 decimal places.)

 p-value

Apr 15th, 2015

Please answer the last three qustions that I sent I will pay 20 if it's correct 

Apr 15th, 2015

 I am attending to some other work. You post them in easy questions. Once I free myself I can attend to them. 

Apr 15th, 2015

I am in the exam now and still 15 mins , can you do that

Apr 15th, 2015

Please I need your help 

Apr 15th, 2015

See in this window it is not easy to digest. Without concentration we cannot provide the correct answer. I do not normally encourage for online exam. I am in India. I should not misguide. I will have some break now. That is why I said so

Apr 15th, 2015

At least one of them please 

Apr 15th, 2015

H0 : μ ≤ 20

H1 : μ > 20

For a)

One tailed

b) decision rule

If t > 1.645 then reject the null hypothesis

Otherwise do not reject

c) z =(21-20)* 6/5 = 1.2

d) since z < 1.645 we do not reject

e) p value = P(z>1.2) = 0.1507


Apr 15th, 2015

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