Find Distance

Line Segment AB

Point A = (-3,5)

Point B = (7,5)

Show proof

Distance of AB = sqrt[(7 - -3)^2 + (5-5)^2]

= sqrt(10^2) = sqrt100 = 10

Can you please solve? Distance

Line Segment CD

C= (1,-3)D=(-6-3)

C= (1,-3)

D=(-6-3)

CD = 7

thank you

Luv you Vincent!!!!!

:)

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