Mean and deviation

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A candy company claims that 19% of its plain candies are orange, and a sample of 200 such candies is randomly selected. a. Find the mean and standard deviation for the number of orange candies in such groups of 200. u= OS (Round to one decimal place as needed.) b. A random sample of 200 candies contains 44 orange candies. Is this result unusual? Does it seem that the claimed rate of 19% is wrong? A. Yes, because 44 is greater than the maximum usual value. Thus, the claimed rate of 19% is probably wrong. B. Yes, because 44 is below the minimum usual value. Thus, the claimed rate of 19% is not necessarily wrong. C. No, because 44 is within the range of usual values. Thus, the claimed rate of 19% is not necessarily wrong. OD. Yes, because 44 is within the range of usual values. Thus, the claimed rate of 19% is probably wrong.
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Mean and deviation
A candy company claims that 19% of its plain candies are orange, and a sample of 200 such candies is
randomly selected.
a. Find the mean and standard deviation for the number of orange candies in ...


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