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Ax By=C With two problems

label Algebra
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schedule 1 Day
account_balance_wallet $5

Apr 17th, 2015

Two equations can be set up from this:

2c + 12t = $83

5c + 3t = $32

What you want to do is multiply one of the equations so that when the two equations are added together, one of the variables can be cancelled out and you solve for the other variable.

You can accomplish this by multiplying both sides of the bottom equation by -4

2c + 12t = $83

-20c - 12t = -$128

-18c = -$128

c = $7.11 which is the cost each chair

Substitute that value in for c in one of the equations and solve for t

2c + 12t = $83

2($7.11) + 12t = $83

$14.22 + 12t = $83

12t = $68.78

t = $5.73 

Apr 17th, 2015

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Apr 17th, 2015
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Apr 17th, 2015
Sep 24th, 2017
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