Suppose 1600 J of heat are added to 4.1 mol of argon gas at a constant pressure

Physics
Tutor: None Selected Time limit: 1 Day

Apr 17th, 2015

the heat cacpacity of 4.1 mole Argon is 

C = 3/2 n R = 3/2*4.1*8.31 = 51.10J/K

b) 960/51.10 = 18.78 K 

c) 

PV = nRT

P deltaV = nR delta T 

deltaV = nR/P *deltaT = 4.1*8.31/120000*18.78 

=0.00533 m^3

Apr 17th, 2015

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