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How many grams of potassium sulfate must be dissolved in 695 grams of acetic

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How many grams of potassium sulfate must be dissolved in 695 grams of acetic acid in order  for the boiling point of the solution to be 135.5 decrees Celsius?

Apr 17th, 2015

molecular weight of acetic acid= 174.259

Moles = x/174.259 

Kb= 3.08

Boiling point of acetic acid = 118.1 deg C

Del T =i* Kb * m (m is molality, Kb is ebullioscopic constant)

135.5 - 118.1 = 2* 3.07 * x/174.259 / 0.695

x = 343.21 gms


Apr 17th, 2015

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Apr 17th, 2015
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