How many grams of potassium sulfate must be dissolved in 695 grams of acetic acid in order for the boiling point of the solution to be 135.5 decrees Celsius?
molecular weight of acetic acid= 174.259
Moles = x/174.259
Boiling point of acetic acid = 118.1 deg C
Del T =i* Kb * m (m is molality, Kb is ebullioscopic constant)
135.5 - 118.1 = 2* 3.07 * x/174.259 / 0.695
x = 343.21 gms
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