Need precalc help with parametric equations

Calculus
Tutor: None Selected Time limit: 1 Day

The position of a bug is described by the parametric equations x=2-12t and y= 1 + 5t, with t in seconds and x,y in centimeters. Explain why the speed of the bug is 13 cm/sec. Change the equations to obtain the description of a bug moving along the same line with a speed of 26 cm/sec. 

Apr 18th, 2015

Vx= dx/dt = -12, Vy=dy/dt = 5, 

V = sqrt(Vx^2+Vy^2) = sqrt(169) = 13 cm/s

the equation is 

x = 2 -24t, y = 1+10t 

Apr 18th, 2015

Hi! Thank you for your help. Just curious: what is Vx and Vy from? What does that mean? 

Apr 18th, 2015

vx =dx/dt  is the velocity in x direction, it mean how fast the object move in x direction 

Apr 18th, 2015

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Apr 18th, 2015
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Apr 18th, 2015
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