Time remaining:
(y+4)^2=2y^2+9+14; Solve for y

Algebra
Tutor: None Selected Time limit: 1 Day

I need to solve for y with this equation, but I'm not sure how to get started.

Apr 19th, 2015

(y + 4)^2 = 2y^2 + 9 + 14

y^2 + 8y + 16 = 2y^2 + 9 + 14

Now

2y^2 - y^2 - 8y + 9 + 14 - 16 = 0

y^2 - 8y + 9 - 2 = 0

y^2 - 8y + 7 = 0

y^2 - y - 7y + 7 = 0

y(y - 1) - 7(y - 1) = 0

(y - 1)(y - 7 )= 0

y - 1 = 0      ,       y - 7 = 0

y = 1           ,       y = 7

Hence y = 1 , 7

Apr 19th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Apr 19th, 2015
...
Apr 19th, 2015
Mar 29th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer