Bill is playing soccer and kicks the ball from ground level with an initial speed of 20 m/s in a direction of 30 degrees above the horizon. g=10m/s^2. What is the range of the ball if t=1 sec

v = 20 m/s

Ѳ = 30 degrees

g = 10 m/s^2

t = 1 sec

Now as we know that

Range = (v^2 * sin2Ѳ) / g

= ( (20)^2 * sin2(30) ) / 10

= ( 400 * sin(60) ) / 10

= 40 * sin60

= 40 * 0.866

= 34.64

Or

Range = 35 meters (approx)

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up