75.8 g of C12H22O11 in 400. g H2O
75.8 g of C12H22O11 / 342.3 g/mol = 0.221 moles sucrose 0.221 moles / 0.400 Kg H2O = 0.553 molal 0.553 molal * 1.86 C/molal = your answer: - 1.029 C
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