pH=pka + log([CH3COO-]/[CH3COOH])
[CH3COOH]=n/v = 0,25 mole/ 250*10^-3 L = 1 mole/L
[CH3COO-]= n/v = 0,8 mole / 250 *10^-3 L = 3,2 mole / L
so : log([CH3COO-]/[CH3COOH])= log(3,2/1) = 0,5051499783
So : pH= 5,2651
what did u plug into the calculater to find pH. Was it the inverse log 0.505?
log( 3,2 ) = 0,505 and the inverse is 10^(0,505) = 3,2
When you did the inverse did you add the negative? 10^(-0.505)?
i keep getting 0.3125
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