##### exponential and logarithms

label Algebra
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8^-x+3=1558..... what is the exact form and the decimal approximation rounding 2 decimal places. I don't understand how to get the decimal approximation

Apr 21st, 2015

8^-x+3=1558

log (base 8) 1558 = 3-x

2.51= 3-x

x= 3-2.51

x= 0.49

Apr 20th, 2015

how do you put the base in the TI 83 to get that answer

Apr 20th, 2015

b y = x= logb(x) = y

8^-x+3=1558 transformed into the logarithmic form is log (base 8) 1558 = 3-x

log (base 8) 1558= 3.54

3.54= 3-x

x= 3-3.54= -0.54

Apr 20th, 2015

I'm sorry I am still not coming up with the same answer when I enter it into the calculator. I am entering in log(8) 1558 is that correct or not in the TI 83?

Apr 20th, 2015

log (base 8) 1558= 3.54 is the exact answer dear

Apr 20th, 2015

but what I am saying is I can't figure out how to put the log (base 8) 1558 in the calculator. I have and it keeps coming up with 1407.0142 as the answer I am asking you how to put it in the calculator to get the answer you got.

Apr 20th, 2015

Hello, thanks for the help

Apr 21st, 2015

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Apr 21st, 2015
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Apr 21st, 2015
Sep 22nd, 2017
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