8^-x+3=1558..... what is the exact form and the decimal approximation rounding 2 decimal places. I don't understand how to get the decimal approximation
log (base 8) 1558 = 3-x
how do you put the base in the TI 83 to get that answer
b y = x= logb(x) = y
8^-x+3=1558 transformed into the logarithmic form is log (base 8) 1558 = 3-x
log (base 8) 1558= 3.54
x= 3-3.54= -0.54
sorry, the answer is -0.54
I'm sorry I am still not coming up with the same answer when I enter it into the calculator. I am entering in log(8) 1558 is that correct or not in the TI 83?
log (base 8) 1558= 3.54 is the exact answer dear
but what I am saying is I can't figure out how to put the log (base 8) 1558 in the calculator. I have and it keeps coming up with 1407.0142 as the answer I am asking you how to put it in the calculator to get the answer you got.
Hello, thanks for the help
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