A bin contains 20 batteries, 6 are defective. If you select two at random.......

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A bin contains 20 batteries, 6 are defective. If you select two at random determine the probability:

a) None of the batteries are good

b) At least one of the batteries is good.

Apr 21st, 2015

14 batteries are good

(a) selection of defective battery can be made by  = 6c2  ways 

6c2 = 6!/[4!*2!] = 15

And number of ways to select 2 batteries = 20c2 = 20!/[18!*2!] = 190

Hence probability = 15/190  = 3/38

(b) if none of the battery is good  then probability = 3/38

hence for at least one good battery = 1-3/38 =35/38

Apr 21st, 2015

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Apr 21st, 2015
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Apr 21st, 2015
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