The polynomial y^3+y^2+my-7 has the same remainder when it is divided by either y-1 or y+1. What is the remainder?
y^3 + y^2 + my - 7 / y+1 = y^2 + m - (m+7)/(y^2+m) (remainder in bold)
y^3 + y^2 + my - 7 / y-1 = y^2 + 2y + 2 + m + (m-5)/(y^2+2y+2+m) (remainder in bold)
These remainders are not the same
Correction: The remainder for the first one is -(m+7)/(y+1)
The remainder of the second is (m-5)/(y-1)
But they are still not the same
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