Time remaining:
What is the remainder?

label Algebra
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

The polynomial y^3+y^2+my-7 has the same remainder when it is divided by either y-1 or y+1.  What is the remainder?

Oct 20th, 2017

Remainder = -m-7

with m= -1 to satisfy that polynomial has the same remainder when it is divided by either y-1 or y+1  

-(-1) -7 =-6

Apr 21st, 2015

Could you explain this better.  How did you come up with that answer?  Maybe show me your work.

Apr 21st, 2015

Sure!

Due to the reminder Theorem  P(1) and P(-1) will give the reminders of dividing by x-1 and x+1 respectively

For the polynomial to have the same reminder when divided by either (y-1) or (y+1) you need to make P(1) = P(-1) and solve for m:

1^3+1^2+1*m -7 = (-1)^3+(-1)^2+(-1)*m -7

1+1+m-7 = -1+1-m -7

2m = -2

m = -1

Now to find the actual reminder in both cases we have to put the value of m that we just found into the polynomial.

We will get: y^3+ y^2 + (-1)y -7 = y^3+ y^2  -y -7

Now let's divide it by y+1 and y-1

y^3+ y^2 -y -7 / y-1 = -6 and same answer is for y^3+ y^2 -y -7/y+1 = -6


If you will just divide y^3+ y^2 +my -7/y-1 or y^3+ y^2 -y -7/y+1  you will get  ( -m-7 ) in both cases and if you use above mentioned Polynomial Remainder Theorem and method to find the value of m, you will get -(-1) -7 = -6. 


Hope this explains it.


Let me know if you have any questions or if you would want me to explain any of this even in more detail.




Apr 21st, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Oct 20th, 2017
...
Oct 20th, 2017
Oct 21st, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer