The system of linear equations has a unique solution. Find the solution using Gaussian elimination or Gauss-Jordan elimination.
Add the first equation to the second one; subtract the first equation multiplied by 2 from the third one:
x + y + z = 12
3y +4z = 56
-3y -2z =-40
Add the second equation to the third one:
2z = 16
Then from the third equation z = 16/2 = 8, from the second equation y = (56-4z)/3 = (56-32)/3 = 24/3 = 8, from the first equation x = 12 - y - z = 12 - 8 - 8 = -4.
Answer: (-4, 8, 8).
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?