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label Chemistry
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A) Calculate the kinetic energy in joules of a 1200-kg automobile moving at 18 m/s

B) convert this energy into calories?

c) what happens to this energy when the automobile brakes to a stop

Oct 18th, 2017

A= kinetic energy= (1/2)(m)(v^2)= 1/2*1200*18= 10,800J

B= kinetic energy J into calories= 

1 cal= 4.1868J

?= 10,800J

10,800*1/4.1868=

2,579.54 calories


C. The kinetic energy is dissipated

Apr 21st, 2015

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