Five green apples and seven red apples are in a bucket. Five apples are to be selected at random, without replacement. Determine the probability that the two green apples and three red apples are selected.
Probability of choosing two green and three red apples is 5 C 2 * 5/12*4/11*7/10*6/9*5/8 = 0.04419 * 10 = 0.4419
5 C 2 = 5*4/2 = 10 is the number of combinations (how many arrangements of 2 G and 3 R exist)
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