The average salaries of teachers in NJ is $62,500 with a standard deviation of $7,500. A person is chosen at random from this group. What is the probability that:

Assume that the salaries distribution is normal. Then reduce the x -estimates to z-estimates and find the corresponding probabilities: z = (x - 62500)/7500

A. P( x > 80000) = P(z > (80000 - 62500)/7500) = P(z > 2.33) = 0.0099

B. P( x < 65000) = P(z < (65000 - 62500)/7500) = P(z < 0.333) = 0.6304

C. P( 60000 < x < 70000) = P(-0.333 < z < 1) = 0.4118