A. What mass of propanol (C3H5OH) must be available to completely consume 6.70 moles of acetic acid (CH3COOH)?
B. What would be the theoretical yield (in grams) of propyl acetate (CH3COOC3H5)?
Molecular mass of propanol = 60.09g/mol
A) According to balanced reaction,
3 moles of acetic acid is required to consume 2 moles of propanol
Hence for one mole of acetic acid propanol required = 2/3 moles
hence for 6.7 moles of acetic acid propanol required = 2/3 *6.7 moles
Hence total mass of propanol requirred = molecular mass*number of moles of propanol
B) Number of moles of propyl acetate generated = 2/3*number of moles of acetic acid consumed = 2/3*6.70 moles
Molecular mass of propyl acetate = 102.81 g/mol
Hence total theoretical yield in grams of propyl acetate = molecular mass*moles
= 6.7*102.81*2/3=459.21 g
can you explain how you found 6.7?
Hey it is given as a initial number of moles of acetic acid. It is given in question, in fact with that information only we are able to calculate all other quantities.
In any chemical reaction you at least need one known quantity to calculate the rest of it.
I hope it helps.
sorry, i should have realized.. thank you!
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