B. If .16moles of Mg metal reacts with excess oxygen gas, what is the mass of the theoretical yield?
C. What is the mass of the excess oxygen gas?
D. If you were only able to collect 2.98g of product, what was your percent yield?
B. 0.16mol Mg---0.16mol MgO, mass of theoretical yield is 0.16mol*40.3=6.45g
D. % yield=2.98/6.45 *100%=46.2%
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?