a. v(t) =9t^2+4t

to get s we integrate v(t) to get

s=3t^3+2t^2

b.s=3(2)^3+2(2)^2

=24 feets

c.{ [3(10)^3+2(10)^2]-[3(5)^3+2(5)^2]}

=3200-425

=2775 feets

So for a.:

s in feet is 3t^3 + 2t^2?

how did you get here from v(t) = 9t^2 +4?

New to calculus is foriegn to me....

tks you for your help mercie

sql help needed

where did I go wrong?

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