1. O = -2. There are four oxygens for -8 total. Since -2 must be left over, the S must = +6

2.0 (All free, uncombined elements have an oxidation number of zero.

This includes diatomic elements such as O_{2} or others like P_{4} and S_{8)}

_{3.The O is -2 and three of them makes -6. Since -1 is left over, the N must be +5}

_{4.Since H = +1, the Cl must be -1 (minus one)}

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