find area under curve with 90 m length and 18.5 m right in middle. first have to find equation of the curve

It sounds like you are describing an inverted parabola with zeros at +45 and -45, with vertex at (0,18.5)

In which case F(x) = -ax^2 + 18.5

when F(x) = 0, x = +/- 45

-a(45)^2 + 18.5 = 0

a = 18.5/45^2

a = 0.0089

F(x) = -0.0089x^2 +18.5

the integral of that is -0.0267x^3 + 18.5x taken from 0 to 45

calculate that, and then multiply by 2 because the area is symmetrical about the y -axis

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up