Time remaining:
Quadractics in factored form finding the vertex

label Algebra
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

y=(x-5)2+4

Apr 24th, 2015

y = (x - 5)^2 + 4

Now simplifying

y = x^2 - 10x + 25 + 4

y = x^2 - 10x + 29

Where    a = 1     b = - 10     c = 29

Now

Co-ordinates of vertex are (h, k), then

h = − b/2a

h = - (- 10) / 2(1)

h = 10 / 2

h = 5

k = c - b^2 / 4a

k = 29 - (-10)^2 / 4(1)

k = 29 - 100/4

k = 29 - 25

k = 4

Hence the co-ordinate of the vertex are (h, k) =(5, 4)

Apr 24th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 24th, 2015
...
Apr 24th, 2015
Jun 24th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer