A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F of magnitude 4.8 N. A normal force (n) and a friction force (f) also act on the box. After the magnitude of F is increased to 6.2 N, what is the acceleration of the box?

a. 0.26 m/s^{2}

b. 0.23 m/s^{2}

c. 0.19 m/s^{2}

d. 0.29 m/s^{2}

e. 0.32 m/s^{2 ( i got a picture of the problem ) }

So the formula is F=ma. You divide 74N by 9.8 which is gravity to get mass. The mass of the box is 7.55. You then subtract the new force (6.2) by the old force (4.8) which equals 1.4. So the new equation is 1.4= (7.55)a.

Then to find the new acceleration, you divide 1.4 by 7.55. The answer is 0.185 m/s^2 which rounds to 0.19 m/s^2. So the answer is D. Hope this helps! C: