Statistics question a.3

Statistics
Tutor: None Selected Time limit: 1 Day

Apr 24th, 2015

Difference in mean heights = 6.3

Sample error of the means 2 * 2.89/(25 -2) = 0.2513

critical value of t  for 99% confidence (23 df) = 2.808

hence        - 2.808 * 0.2513   < d -6.3 <2.808 * 0.2513

                                 -0.706    < d -6.3< 0.706

                                                      5.594   <d< 7.006

Lower limit 5.594

upper limit 7.006

Apr 24th, 2015

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