Would this be solved with Logs?

Algebra
Tutor: None Selected Time limit: 1 Day

1.03^x=37.45 I need to solve for x in this equation. I don't know how.

Apr 24th, 2015

log(1.03^x)=log37.45

xlog1.03=log37.45

x=122.57...................................................................................

Apr 24th, 2015

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Apr 24th, 2015
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Apr 24th, 2015
Dec 6th, 2016
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