Time remaining:
find velocity and time equation

label Physics
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about  9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6380 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth? 

Apr 24th, 2015

Centripetal acceleration=v2/R

So, 9.81=v2/6380*103

v=7911.2 m/s

…………………………….

Time period of revolution=2*pi*R/v

  =2*3.14*6380*103/7911.2=5067 sec


Apr 24th, 2015

The number of significant digits is set to 3;

Apr 24th, 2015

v=7.91*103 m/sec or 7.91 km/sec

……………………………

t=5.07*10.3 sec=1.41 hr

Just check the units.


Apr 24th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Apr 24th, 2015
...
Apr 24th, 2015
Oct 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer