Time remaining:
find velocity and time equation

Physics
Tutor: None Selected Time limit: 0 Hours

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about  9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6380 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth? 

Apr 24th, 2015

Centripetal acceleration=v2/R

So, 9.81=v2/6380*103

v=7911.2 m/s

…………………………….

Time period of revolution=2*pi*R/v

  =2*3.14*6380*103/7911.2=5067 sec


Apr 24th, 2015

The number of significant digits is set to 3;

Apr 24th, 2015

v=7.91*103 m/sec or 7.91 km/sec

……………………………

t=5.07*10.3 sec=1.41 hr

Just check the units.


Apr 24th, 2015

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