find the velocity in calculus

Calculus
Tutor: None Selected Time limit: 1 Day

Apr 24th, 2015

v(t)  = 9t*t + 4t

at t=0, s=0

a) d s(t)/dt = 9t*t + 4t

=> s = (9*t*t*t/3 ) + 4t*t/2 +c

Now at t=0, s=0

 Thus, 0=0+0+c => c = 0

Hence s(t) = 3t^3   + 2t^2 = t*t(3t+2)


b) after 2 s

s(t) = s(2) = 2*2(3*2+2) = 32 ft

c) s(10) -s(5) = 10*10(10*3+2) -5*5(5*3+2) 

= 100*32 - 25*17

=2775 ft

Hence change in position from 5 to 10 s is 2775 ft


Apr 24th, 2015

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Apr 24th, 2015
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Apr 24th, 2015
Dec 3rd, 2016
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