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Please help me solve using poisson distribution

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a well-mixed cookie dough will produce cookies with a mean of 5 chocolate chips apiece. 

what is the probability of getting a cookie with more than 4 chips?

Apr 25th, 2015

Here lambda = 5

So probability = [ 1-e^-5 ( 5^0/o! + 5^1/1! + 5^2/2! + 5^3 /3! + 5^4/4!) ]

                      = [ 1- 0.000674 +0.0337 + 0.0842 + 0.140 + 0.1755]

                     = 1 - 0.44

                     = 0.56

Answer: probability p = 0.56

Apr 25th, 2015

Can you try this problem please? A well-mixed cookie dough will produce cookies with a mean of 7 chocolate chips apiece. 

what is the probability of getting a cookie with more than 1 chips?


Apr 25th, 2015

Please note that the second step is missing a bracket sign:

So the second step is = [ 1- ( 0.000674 + 0.0337 + 0.0842 + 0.140 + 0.1755) ]

Still final answer remains the same as before : 1- 0.44 = 0.56

Apr 25th, 2015

THIS IS DIFFERENT FROM ORIGINAL - Can you try this problem please? A well-mixed cookie dough will produce cookies with a mean of 7 chocolate chips apiece. 

what is the probability of getting a cookie with more than 1 chips?


Apr 25th, 2015

If lambda is 7 then

Probability = [ 1- P (x=0 - P (x=1)]

                  = [ 1-0.0073 ]

                    = 0.9927

Hope this helps.

Apr 25th, 2015

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