The height h, in feet, of a golf ball t seconds after it has been hit is given by the equation h = −16t2 + 62t. How many seconds after the ball is hit will the height of the ball be 42 feet? Round answers to nearest hundredth.
h = −16t2 + 62t.
42= −16t2 + 62t
-16t^2 + 62t -42 = 0
-8t^2 + 31t - 21 = 0
delta = 31²- 672 = 961 - 672 = 289 > 0
so : t1 = (-31 - 1.002 )/(-16) = 2.0005
or t2= (-31 + 1.002 )/(-16) = 1.87
So t = 2 s
good luck and please if you need sommething else please tell me first
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