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Mathematics
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Apr 24th, 2015

a. Ho: p=.10  Ha: p< .10

b. level of significance=.05

c. CV: -1.645 Reject Ho if z< -1.645

d. test stat: z= (.07-.1)/sqrt(.1*.9/150)= -1.22

e. Fail to reject Ho.

f.The test stat is not in the rejection region

g. p-value=0.11

h. yes, the plant is in compliance with the noise pollution code.

Apr 25th, 2015

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