What quantity of heat, in joules, is released when 20.0 g of water at 36.0°C is cooled to ice at -24.0°C. and
Q= heat provided by cooling water from 36 c to 0c + latent heat at 0c + cooling of ice to -24
= 20 g x 4.18 j/g k x 36 + 20g ( 152 j/g) + 20x 2.11 j/g k x 24
= 4270.2 J
Answer: 4270.2 J.
Please note that I have assumed latent heat of ice at 152 j/g as it is not given . please verify and correct it if necessary.
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