What quantity of heat in joules is released when 45.0 grams of water at 45.0 degrees Celsius is cooled to ice:
Specific heat of ice- 2.09j/g
Specific heat of water-4.18J/g
Specific heat of steam-2.03J/g
Heat of fusion of water- 334J/g
Heat of vaporization of water- 2260K/g
Heat release = heat removed to cool water + heat removed to make ice
=. 45 x 4.18 x 45 + 45 x 334
= 8465.5 + 15030
= 23495.6 J
Answer: 23495.6 j heat release
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