Time remaining:
A question about caliometry

Chemistry
Tutor: None Selected Time limit: 0 Hours

What quantity of heat in joules is released when 45.0 grams of water at 45.0 degrees Celsius is cooled to ice:

Specific heat of ice- 2.09j/g

Specific heat of water-4.18J/g

Specific heat of steam-2.03J/g

Heat of fusion of water- 334J/g

Heat of vaporization of water- 2260K/g

Apr 25th, 2015

Heat release = heat removed to cool water + heat removed to make ice

                     =. 45 x 4.18 x 45 + 45 x 334

                     = 8465.5 + 15030

                    = 23495.6 J

Answer: 23495.6 j heat release

Apr 25th, 2015

great job!

May 3rd, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Apr 25th, 2015
...
Apr 25th, 2015
Feb 24th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer