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A question about caliometry

label Chemistry
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What quantity of heat in joules is released when 45.0 grams of water at 45.0 degrees Celsius is cooled to ice:

Specific heat of ice- 2.09j/g

Specific heat of water-4.18J/g

Specific heat of steam-2.03J/g

Heat of fusion of water- 334J/g

Heat of vaporization of water- 2260K/g

Apr 25th, 2015

Heat release = heat removed to cool water + heat removed to make ice

                     =. 45 x 4.18 x 45 + 45 x 334

                     = 8465.5 + 15030

                    = 23495.6 J

Answer: 23495.6 j heat release

Apr 25th, 2015

great job!

May 3rd, 2015

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